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/* Since x and y's defaults have already been specified in xyout()'s prototype, they cannot be repeated here */ void xyout(char *str, int x, int y) { if(!x) x = wherex(); if(!y) y = wherey(); gotoxy(x, y); cout << str; }

If you decide to buy an Internet Refrigerator, it is a good idea to install your Ethernet connection and your cable connection to the refrigerator s site before the refrigerator is delivered Otherwise, the most your new Internet th Refrigerator will be able to do is keep food cold That s so 20 century

If you try specifying new or even the same default values in xyout( ) s definition, the compiler will display an error and not compile your program Even though default arguments cannot be redefined, each version of an overloaded function can specify different default arguments When defining parameters, it is important to understand that all parameters that take default values must appear to the right of those that do not That is, you cannot specify a nondefaulting parameter once you have defined a parameter that takes a default value For example, it would have been incorrect to define xyout( ) as:

// wrong! void xyout(int x = 0, int y = 0, char *str)

// wrong ! int f(int i, int j=10, int k)

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Once the default parameters begin, no nondefaulting parameter may occur in the list You can also use default parameters in an object s constructor For example, here is a slightly different version of the queue( ) constructor function, shown earlier in this chapter

To begin with, let s convert to metric units, rounding off to keep the numbers relatively simple 180 lb is 800 N The fact that the player is 6 ft tall is irrelevant (at least to us, perhaps not to the coach) Eight inches is 02 m And 450 lb of force is 2000 N In a real-life situation, the force applied would not be constant However, to keep things simple we can use the average force and assume a constant force (equal to the average force) during the time the basketball player is accelerating up from the bent-knee position Recall that force equals mass times acceleration (F 5 ma), so a constant force means a constant acceleration And a constant acceleration means that the velocity is increasing linearly (in a straight line) This last point is helpful, because it means that wherever we have a constant acceleration, instead of having to figure out the increasing velocity at each point in time, we can simply take the average of the initial and final velocity, and apply that average velocity over the same period of time and get the same mathematical result We break the problem up into the same steps as previously The first step is to determine maximum velocity at the end of step 1 Then using this as the starting velocity of step 2 and applying the downward acceleration of gravity, we calculate the distance traveled until the velocity is zero: This is the height of the jump Before we solve the problem, let s review and derive some basic formulas of motion By definition, speed or velocity is the distance traveled divided by time See Eq (12-1) This will be used to relate the velocity of the jump to the height of the jump (Throughout this section we will use speed and velocity interchangeably, Strictly speaking, velocity and acceleration are vectors, and speed is scalar But for our purposes we are only dealing with motion in the up and down direction Therefore to keep things simple, we will treat velocity and acceleration as scalars and use positive value for the up direction and negative value for the down direction) v 5 d /t (12-1).

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